Base | Representation |
---|---|
bin | 101110101100001011… |
… | …110010110010101011 |
3 | 11210101212212020220101 |
4 | 232230023302302223 |
5 | 1310133123204120 |
6 | 35010405010231 |
7 | 3423231660016 |
oct | 565413626253 |
9 | 153355766811 |
10 | 50133413035 |
11 | 1a297006262 |
12 | 98716b3977 |
13 | 495c5b1b54 |
14 | 25d833c37d |
15 | 148644990a |
hex | bac2f2cab |
50133413035 has 32 divisors (see below), whose sum is σ = 62162380800. Its totient is φ = 38797100160.
The previous prime is 50133412997. The next prime is 50133413047. The reversal of 50133413035 is 53031433105.
50133413035 is nontrivially palindromic in base 16.
It is not a de Polignac number, because 50133413035 - 219 = 50132888747 is a prime.
It is a super-2 number, since 2×501334130352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50133412994 and 50133413012.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7244397 + ... + 7251313.
It is an arithmetic number, because the mean of its divisors is an integer number (1942574400).
Almost surely, 250133413035 is an apocalyptic number.
50133413035 is a deficient number, since it is larger than the sum of its proper divisors (12028967765).
50133413035 is a wasteful number, since it uses less digits than its factorization.
50133413035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7371.
The product of its (nonzero) digits is 8100, while the sum is 28.
The spelling of 50133413035 in words is "fifty billion, one hundred thirty-three million, four hundred thirteen thousand, thirty-five".
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