Base | Representation |
---|---|
bin | 101110101100001100… |
… | …010000011101011001 |
3 | 11210101220002102121001 |
4 | 232230030100131121 |
5 | 1310133141101203 |
6 | 35010411345001 |
7 | 3423233004214 |
oct | 565414203531 |
9 | 153356072531 |
10 | 50133534553 |
11 | 1a297089593 |
12 | 9871752161 |
13 | 495c62525b |
14 | 25d837077b |
15 | 148647091d |
hex | bac310759 |
50133534553 has 4 divisors (see below), whose sum is σ = 50134848228. Its totient is φ = 50132220880.
The previous prime is 50133534551. The next prime is 50133534557. The reversal of 50133534553 is 35543533105.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8048242944 + 42085291609 = 89712^2 + 205147^2 .
It is a cyclic number.
It is not a de Polignac number, because 50133534553 - 21 = 50133534551 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50133534551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 597826 + ... + 676507.
It is an arithmetic number, because the mean of its divisors is an integer number (12533712057).
Almost surely, 250133534553 is an apocalyptic number.
It is an amenable number.
50133534553 is a deficient number, since it is larger than the sum of its proper divisors (1313675).
50133534553 is a wasteful number, since it uses less digits than its factorization.
50133534553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1313674.
The product of its (nonzero) digits is 202500, while the sum is 37.
The spelling of 50133534553 in words is "fifty billion, one hundred thirty-three million, five hundred thirty-four thousand, five hundred fifty-three".
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