Base | Representation |
---|---|
bin | 100100011110101001111… |
… | …0011010000001110001011 |
3 | 122202022001200121001200101 |
4 | 1020331103303100032023 |
5 | 1124120404442413042 |
6 | 14355121530150231 |
7 | 1025136331321006 |
oct | 110752363201613 |
9 | 18668050531611 |
10 | 5013632779147 |
11 | 16632a6aa9293 |
12 | 68b813582377 |
13 | 2a4a2559a7a5 |
14 | 13493818c53d |
15 | 8a6394b86b7 |
hex | 48f53cd038b |
5013632779147 has 2 divisors, whose sum is σ = 5013632779148. Its totient is φ = 5013632779146.
The previous prime is 5013632779121. The next prime is 5013632779153. The reversal of 5013632779147 is 7419772363105.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5013632779147 is a prime.
It is not a weakly prime, because it can be changed into another prime (5013632779157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506816389573 + 2506816389574.
It is an arithmetic number, because the mean of its divisors is an integer number (2506816389574).
Almost surely, 25013632779147 is an apocalyptic number.
5013632779147 is a deficient number, since it is larger than the sum of its proper divisors (1).
5013632779147 is an equidigital number, since it uses as much as digits as its factorization.
5013632779147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6667920, while the sum is 55.
The spelling of 5013632779147 in words is "five trillion, thirteen billion, six hundred thirty-two million, seven hundred seventy-nine thousand, one hundred forty-seven".
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