Base | Representation |
---|---|
bin | 101110101100011010… |
… | …011011001001110101 |
3 | 11210102011002002222221 |
4 | 232230122123021311 |
5 | 1310140113421443 |
6 | 35011023122341 |
7 | 3423306402532 |
oct | 565432331165 |
9 | 153364062887 |
10 | 50137248373 |
11 | 1a299195863 |
12 | 9872a433b1 |
13 | 4960325794 |
14 | 25d8a59d89 |
15 | 1486955eed |
hex | bac69b275 |
50137248373 has 2 divisors, whose sum is σ = 50137248374. Its totient is φ = 50137248372.
The previous prime is 50137248347. The next prime is 50137248391. The reversal of 50137248373 is 37384273105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38701512529 + 11435735844 = 196727^2 + 106938^2 .
It is a cyclic number.
It is not a de Polignac number, because 50137248373 - 221 = 50135151221 is a prime.
It is a super-2 number, since 2×501372483732 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50137248673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25068624186 + 25068624187.
It is an arithmetic number, because the mean of its divisors is an integer number (25068624187).
Almost surely, 250137248373 is an apocalyptic number.
It is an amenable number.
50137248373 is a deficient number, since it is larger than the sum of its proper divisors (1).
50137248373 is an equidigital number, since it uses as much as digits as its factorization.
50137248373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 423360, while the sum is 43.
The spelling of 50137248373 in words is "fifty billion, one hundred thirty-seven million, two hundred forty-eight thousand, three hundred seventy-three".
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