Base | Representation |
---|---|
bin | 100100011110111100101… |
… | …1011010101100010110111 |
3 | 122202100200200102121212010 |
4 | 1020331321123111202313 |
5 | 1124123203043344303 |
6 | 14355304320255303 |
7 | 1025161065063315 |
oct | 110757133254267 |
9 | 18670620377763 |
10 | 5014264043703 |
11 | 16635a0370732 |
12 | 68b96aa71533 |
13 | 2a4ac62c1b05 |
14 | 134997d530b5 |
15 | 8a674b0ec03 |
hex | 48f796d58b7 |
5014264043703 has 24 divisors (see below), whose sum is σ = 6991678053360. Its totient is φ = 3196279102720.
The previous prime is 5014264043693. The next prime is 5014264043707. The reversal of 5014264043703 is 3073404624105.
It is a de Polignac number, because none of the positive numbers 2k-5014264043703 is a prime.
It is a super-2 number, since 2×50142640437032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5014264043707) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3556783 + ... + 4762271.
It is an arithmetic number, because the mean of its divisors is an integer number (291319918890).
Almost surely, 25014264043703 is an apocalyptic number.
5014264043703 is a deficient number, since it is larger than the sum of its proper divisors (1977414009657).
5014264043703 is a wasteful number, since it uses less digits than its factorization.
5014264043703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1208159 (or 1208136 counting only the distinct ones).
The product of its (nonzero) digits is 241920, while the sum is 39.
Adding to 5014264043703 its reverse (3073404624105), we get a palindrome (8087668667808).
The spelling of 5014264043703 in words is "five trillion, fourteen billion, two hundred sixty-four million, forty-three thousand, seven hundred three".
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