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5015310434129 is a prime number
BaseRepresentation
bin100100011111011011111…
…0010111111111101010001
3122202110101121101202200002
41020332313302333331101
51124132323432343004
614400000220135345
71025226032206262
oct110766762777521
918673347352602
105015310434129
111663a87a9a306
12690001397555
132a4c32022448
14134a56cd8969
158a6d690661e
hex48fb7cbff51

5015310434129 has 2 divisors, whose sum is σ = 5015310434130. Its totient is φ = 5015310434128.

The previous prime is 5015310434027. The next prime is 5015310434149. The reversal of 5015310434129 is 9214340135105.

It is a happy number.

5015310434129 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4093633632529 + 921676801600 = 2023273^2 + 960040^2 .

It is a cyclic number.

It is not a de Polignac number, because 5015310434129 - 28 = 5015310433873 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5015310434092 and 5015310434101.

It is not a weakly prime, because it can be changed into another prime (5015310434149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507655217064 + 2507655217065.

It is an arithmetic number, because the mean of its divisors is an integer number (2507655217065).

Almost surely, 25015310434129 is an apocalyptic number.

It is an amenable number.

5015310434129 is a deficient number, since it is larger than the sum of its proper divisors (1).

5015310434129 is an equidigital number, since it uses as much as digits as its factorization.

5015310434129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 38.

The spelling of 5015310434129 in words is "five trillion, fifteen billion, three hundred ten million, four hundred thirty-four thousand, one hundred twenty-nine".