Base | Representation |
---|---|
bin | 100100011111011011111… |
… | …1010000111111111011101 |
3 | 122202110101201220122222011 |
4 | 1020332313322013333131 |
5 | 1124132324422131140 |
6 | 14400000324151221 |
7 | 1025226054116143 |
oct | 110766772077735 |
9 | 18673351818864 |
10 | 5015312302045 |
11 | 1663a89055741 |
12 | 690001b38511 |
13 | 2a4c32527716 |
14 | 134a57263593 |
15 | 8a6d6b74cea |
hex | 48fb7e87fdd |
5015312302045 has 32 divisors (see below), whose sum is σ = 6285329043840. Its totient is φ = 3838608264960.
The previous prime is 5015312302037. The next prime is 5015312302061. The reversal of 5015312302045 is 5402032135105.
It is not a de Polignac number, because 5015312302045 - 23 = 5015312302037 is a prime.
It is a super-2 number, since 2×50153123020452 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5015312301998 and 5015312302016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2800075 + ... + 4227415.
It is an arithmetic number, because the mean of its divisors is an integer number (196416532620).
Almost surely, 25015312302045 is an apocalyptic number.
It is an amenable number.
5015312302045 is a deficient number, since it is larger than the sum of its proper divisors (1270016741795).
5015312302045 is a wasteful number, since it uses less digits than its factorization.
5015312302045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1427725.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 5015312302045 in words is "five trillion, fifteen billion, three hundred twelve million, three hundred two thousand, forty-five".
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