Base | Representation |
---|---|
bin | 100100011111011011111… |
… | …1010100010110111100011 |
3 | 122202110101202010020222102 |
4 | 1020332313322202313203 |
5 | 1124132324434142011 |
6 | 14400000330401015 |
7 | 1025226055055120 |
oct | 110766772426743 |
9 | 18673352106872 |
10 | 5015312412131 |
11 | 1663a8912041a |
12 | 690001b9016b |
13 | 2a4c32565868 |
14 | 134a57291747 |
15 | 8a6d6b9773b |
hex | 48fb7ea2de3 |
5015312412131 has 32 divisors (see below), whose sum is σ = 5989279994880. Its totient is φ = 4106239733376.
The previous prime is 5015312412119. The next prime is 5015312412157. The reversal of 5015312412131 is 1312142135105.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 5015312412131 - 230 = 5014238670307 is a prime.
It is a super-2 number, since 2×50153124121312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5015312412094 and 5015312412103.
It is not an unprimeable number, because it can be changed into a prime (5015312412731) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 622320380 + ... + 622328438.
It is an arithmetic number, because the mean of its divisors is an integer number (187164999840).
Almost surely, 25015312412131 is an apocalyptic number.
5015312412131 is a deficient number, since it is larger than the sum of its proper divisors (973967582749).
5015312412131 is a wasteful number, since it uses less digits than its factorization.
5015312412131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12963.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 5015312412131 its reverse (1312142135105), we get a palindrome (6327454547236).
The spelling of 5015312412131 in words is "five trillion, fifteen billion, three hundred twelve million, four hundred twelve thousand, one hundred thirty-one".
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