Base | Representation |
---|---|
bin | 10110110011101001101100… |
… | …01111111001001010001101 |
3 | 20120120121021202101000110110 |
4 | 23121310312033321022031 |
5 | 23033202320233020331 |
6 | 254400025404030233 |
7 | 13364311056521466 |
oct | 1331646617711215 |
9 | 216517252330413 |
10 | 50153243251341 |
11 | 14a86964360a4a |
12 | 576004b832379 |
13 | 21ca579ba5669 |
14 | c55603a01d6d |
15 | 5be903332946 |
hex | 2d9d363f928d |
50153243251341 has 16 divisors (see below), whose sum is σ = 68168048223744. Its totient is φ = 32791363695024.
The previous prime is 50153243251337. The next prime is 50153243251357. The reversal of 50153243251341 is 14315234235105.
It is not a de Polignac number, because 50153243251341 - 22 = 50153243251337 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 50153243251341.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50153243251301) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 549554865 + ... + 549646118.
It is an arithmetic number, because the mean of its divisors is an integer number (4260503013984).
Almost surely, 250153243251341 is an apocalyptic number.
It is an amenable number.
50153243251341 is a deficient number, since it is larger than the sum of its proper divisors (18014804972403).
50153243251341 is a wasteful number, since it uses less digits than its factorization.
50153243251341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1099201280.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 50153243251341 its reverse (14315234235105), we get a palindrome (64468477486446).
The spelling of 50153243251341 in words is "fifty trillion, one hundred fifty-three billion, two hundred forty-three million, two hundred fifty-one thousand, three hundred forty-one".
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