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5015343540331 = 23218058414797
BaseRepresentation
bin100100011111011100111…
…0001010010100001101011
3122202110110220200201211201
41020332321301102201223
51124132410421242311
614400003401505031
71025226613462645
oct110767161224153
918673426621751
105015343540331
111663aa4751503
126900104a2177
132a4c38b44207
14134a5b475895
158a6d97959c1
hex48fb9c5286b

5015343540331 has 4 divisors (see below), whose sum is σ = 5233401955152. Its totient is φ = 4797285125512.

The previous prime is 5015343540307. The next prime is 5015343540371. The reversal of 5015343540331 is 1330453435105.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5015343540331 - 25 = 5015343540299 is a prime.

It is a super-2 number, since 2×50153435403312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5015343540371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109029207376 + ... + 109029207421.

It is an arithmetic number, because the mean of its divisors is an integer number (1308350488788).

Almost surely, 25015343540331 is an apocalyptic number.

5015343540331 is a deficient number, since it is larger than the sum of its proper divisors (218058414821).

5015343540331 is a wasteful number, since it uses less digits than its factorization.

5015343540331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218058414820.

The product of its (nonzero) digits is 162000, while the sum is 37.

Adding to 5015343540331 its reverse (1330453435105), we get a palindrome (6345796975436).

The spelling of 5015343540331 in words is "five trillion, fifteen billion, three hundred forty-three million, five hundred forty thousand, three hundred thirty-one".

Divisors: 1 23 218058414797 5015343540331