501614705014117 has 2 divisors, whose sum is σ = 501614705014118. Its totient is φ = 501614705014116.

The previous prime is 501614705014091. The next prime is 501614705014151. The reversal of 501614705014117 is 711410507416105.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 410533812349956 + 91080892664161 = 20261634^2 + 9543631^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-501614705014117 is a prime.

It is a super-3 number, since 3×501614705014117³ (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (501614705014177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250807352507058 + 250807352507059.

It is an arithmetic number, because the mean of its divisors is an integer number (250807352507059).

Almost surely, 2^{501614705014117} is an apocalyptic number.

It is an amenable number.

501614705014117 is a deficient number, since it is larger than the sum of its proper divisors (1).

501614705014117 is an equidigital number, since it uses as much as digits as its factorization.

501614705014117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 117600, while the sum is 43.

The spelling of 501614705014117 in words is "five hundred one trillion, six hundred fourteen billion, seven hundred five million, fourteen thousand, one hundred seventeen".