Base | Representation |
---|---|
bin | 100100011111110101010… |
… | …0100011000101011100101 |
3 | 122202112120222020001101002 |
4 | 1020333222210120223211 |
5 | 1124141100013210003 |
6 | 14400220525243045 |
7 | 1025256114355052 |
oct | 110775244305345 |
9 | 18675528201332 |
10 | 5016162241253 |
11 | 16643848a5639 |
12 | 6901ba703485 |
13 | 2a5039644127 |
14 | 134ad80ac029 |
15 | 8a7365b3a88 |
hex | 48fea918ae5 |
5016162241253 has 2 divisors, whose sum is σ = 5016162241254. Its totient is φ = 5016162241252.
The previous prime is 5016162241241. The next prime is 5016162241297. The reversal of 5016162241253 is 3521422616105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4987106311489 + 29055929764 = 2233183^2 + 170458^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5016162241253 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5016162241553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2508081120626 + 2508081120627.
It is an arithmetic number, because the mean of its divisors is an integer number (2508081120627).
Almost surely, 25016162241253 is an apocalyptic number.
It is an amenable number.
5016162241253 is a deficient number, since it is larger than the sum of its proper divisors (1).
5016162241253 is an equidigital number, since it uses as much as digits as its factorization.
5016162241253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 38.
Adding to 5016162241253 its reverse (3521422616105), we get a palindrome (8537584857358).
The spelling of 5016162241253 in words is "five trillion, sixteen billion, one hundred sixty-two million, two hundred forty-one thousand, two hundred fifty-three".
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