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50182726955149 is a prime number
BaseRepresentation
bin10110110100100000100111…
…00111010011000010001101
320120200102101112011100121101
423122100103213103002031
523034143211100031044
6254421343154103101
713366403520051565
oct1332202347230215
9216612345140541
1050182726955149
1114a98414118008
1257658b987aa91
1322002982cb049
14c56bdd651da5
155c057b974cd4
hex2da4139d308d

50182726955149 has 2 divisors, whose sum is σ = 50182726955150. Its totient is φ = 50182726955148.

The previous prime is 50182726955029. The next prime is 50182726955219. The reversal of 50182726955149 is 94155962728105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 50119419363049 + 63307592100 = 7079507^2 + 251610^2 .

It is a cyclic number.

It is not a de Polignac number, because 50182726955149 - 217 = 50182726824077 is a prime.

It is a super-3 number, since 3×501827269551493 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50182726959149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25091363477574 + 25091363477575.

It is an arithmetic number, because the mean of its divisors is an integer number (25091363477575).

Almost surely, 250182726955149 is an apocalyptic number.

It is an amenable number.

50182726955149 is a deficient number, since it is larger than the sum of its proper divisors (1).

50182726955149 is an equidigital number, since it uses as much as digits as its factorization.

50182726955149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432000, while the sum is 64.

The spelling of 50182726955149 in words is "fifty trillion, one hundred eighty-two billion, seven hundred twenty-six million, nine hundred fifty-five thousand, one hundred forty-nine".