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5019988124153 is a prime number
BaseRepresentation
bin100100100001100111010…
…0110111110000111111001
3122202220110121022001001202
41021003032212332013321
51124221413424433103
614402052315223545
71025452662004442
oct111031646760771
918686417261052
105019988124153
111665a68475032
12690aa7a47bb5
132a54c9171572
14134d7c25a2c9
158a8ac3e3988
hex490ce9be1f9

5019988124153 has 2 divisors, whose sum is σ = 5019988124154. Its totient is φ = 5019988124152.

The previous prime is 5019988124033. The next prime is 5019988124189. The reversal of 5019988124153 is 3514218899105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5019988124089 + 64 = 2240533^2 + 8^2 .

It is a cyclic number.

It is not a de Polignac number, because 5019988124153 - 218 = 5019987862009 is a prime.

It is not a weakly prime, because it can be changed into another prime (5019988124653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2509994062076 + 2509994062077.

It is an arithmetic number, because the mean of its divisors is an integer number (2509994062077).

Almost surely, 25019988124153 is an apocalyptic number.

It is an amenable number.

5019988124153 is a deficient number, since it is larger than the sum of its proper divisors (1).

5019988124153 is an equidigital number, since it uses as much as digits as its factorization.

5019988124153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3110400, while the sum is 56.

The spelling of 5019988124153 in words is "five trillion, nineteen billion, nine hundred eighty-eight million, one hundred twenty-four thousand, one hundred fifty-three".