Base | Representation |
---|---|
bin | 101110110000001001… |
… | …110100101011000111 |
3 | 11210120112011111100021 |
4 | 232300021310223013 |
5 | 1310302200132234 |
6 | 35021144200011 |
7 | 3425001001432 |
oct | 566011645307 |
9 | 153515144307 |
10 | 50200005319 |
11 | 1a32065a002 |
12 | 988ba69007 |
13 | 4970329579 |
14 | 2603114819 |
15 | 148c2009b4 |
hex | bb0274ac7 |
50200005319 has 2 divisors, whose sum is σ = 50200005320. Its totient is φ = 50200005318.
The previous prime is 50200005311. The next prime is 50200005329. The reversal of 50200005319 is 91350000205.
50200005319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50200005319 - 23 = 50200005311 is a prime.
It is a super-2 number, since 2×502000053192 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50200005293 and 50200005302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50200005311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25100002659 + 25100002660.
It is an arithmetic number, because the mean of its divisors is an integer number (25100002660).
Almost surely, 250200005319 is an apocalyptic number.
50200005319 is a deficient number, since it is larger than the sum of its proper divisors (1).
50200005319 is an equidigital number, since it uses as much as digits as its factorization.
50200005319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 25.
The spelling of 50200005319 in words is "fifty billion, two hundred million, five thousand, three hundred nineteen".
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