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50202561131 is a prime number
BaseRepresentation
bin101110110000010011…
…100100101001101011
311210120200222100020222
4232300103210221223
51310303323424011
635021315040255
73425031504662
oct566023445153
9153520870228
1050202561131
111a322045248
1298908a008b
134970a12998
1426035bbdd9
15148c557ddb
hexbb04e4a6b

50202561131 has 2 divisors, whose sum is σ = 50202561132. Its totient is φ = 50202561130.

The previous prime is 50202561109. The next prime is 50202561133. The reversal of 50202561131 is 13116520205.

50202561131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 50202561131 - 214 = 50202544747 is a prime.

It is a super-2 number, since 2×502025611312 (a number of 22 digits) contains 22 as substring.

Together with 50202561133, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50202561131.

It is not a weakly prime, because it can be changed into another prime (50202561133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25101280565 + 25101280566.

It is an arithmetic number, because the mean of its divisors is an integer number (25101280566).

Almost surely, 250202561131 is an apocalyptic number.

50202561131 is a deficient number, since it is larger than the sum of its proper divisors (1).

50202561131 is an equidigital number, since it uses as much as digits as its factorization.

50202561131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1800, while the sum is 26.

The spelling of 50202561131 in words is "fifty billion, two hundred two million, five hundred sixty-one thousand, one hundred thirty-one".