Base | Representation |
---|---|
bin | 10110110101001100110101… |
… | …01000111001001111110111 |
3 | 20120202200200000111102022121 |
4 | 23122212122220321033313 |
5 | 23040040321041300310 |
6 | 254440311012340411 |
7 | 13401204026205412 |
oct | 1332463250711767 |
9 | 216680600442277 |
10 | 50206467134455 |
11 | 14aa74968aa105 |
12 | 576a424314707 |
13 | 22025ac826918 |
14 | c58012576b79 |
15 | 5c0ebac420da |
hex | 2da99aa393f7 |
50206467134455 has 16 divisors (see below), whose sum is σ = 62330379115680. Its totient is φ = 38776988430208.
The previous prime is 50206467134429. The next prime is 50206467134477. The reversal of 50206467134455 is 55443176460205.
It is a cyclic number.
It is not a de Polignac number, because 50206467134455 - 29 = 50206467133943 is a prime.
It is a super-3 number, since 3×502064671344553 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12417712 + ... + 15956581.
It is an arithmetic number, because the mean of its divisors is an integer number (3895648694730).
Almost surely, 250206467134455 is an apocalyptic number.
50206467134455 is a deficient number, since it is larger than the sum of its proper divisors (12123911981225).
50206467134455 is a wasteful number, since it uses less digits than its factorization.
50206467134455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28386530.
The product of its (nonzero) digits is 12096000, while the sum is 52.
The spelling of 50206467134455 in words is "fifty trillion, two hundred six billion, four hundred sixty-seven million, one hundred thirty-four thousand, four hundred fifty-five".
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