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5021134034113 = 7738877323163
BaseRepresentation
bin100100100010001001011…
…1010010001010011000001
3122210000102110112022000101
41021010102322101103001
51124231240303042423
614402402132122401
71025523245042011
oct111042272212301
918700373468011
105021134034113
1116664a629715a
12691167766401
132a564c6a7ab2
1413504a509c41
158a927ce77ad
hex49112e914c1

5021134034113 has 8 divisors (see below), whose sum is σ = 5033298495168. Its totient is φ = 5008984222704.

The previous prime is 5021134034101. The next prime is 5021134034143. The reversal of 5021134034113 is 3114304311205.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5021134034113 - 217 = 5021133903041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5021134034143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2975931 + ... + 4347232.

It is an arithmetic number, because the mean of its divisors is an integer number (629162311896).

Almost surely, 25021134034113 is an apocalyptic number.

It is an amenable number.

5021134034113 is a deficient number, since it is larger than the sum of its proper divisors (12164461055).

5021134034113 is an equidigital number, since it uses as much as digits as its factorization.

5021134034113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7324823.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 5021134034113 its reverse (3114304311205), we get a palindrome (8135438345318).

The spelling of 5021134034113 in words is "five trillion, twenty-one billion, one hundred thirty-four million, thirty-four thousand, one hundred thirteen".

Divisors: 1 773 887 685651 7323163 5660804999 6495645581 5021134034113