Base | Representation |
---|---|
bin | 100100100010001001011… |
… | …1010010001010011011111 |
3 | 122210000102110112022001111 |
4 | 1021010102322101103133 |
5 | 1124231240303043033 |
6 | 14402402132122451 |
7 | 1025523245042053 |
oct | 111042272212337 |
9 | 18700373468044 |
10 | 5021134034143 |
11 | 16664a6297187 |
12 | 691167766427 |
13 | 2a564c6a7b06 |
14 | 13504a509c63 |
15 | 8a927ce77cd |
hex | 49112e914df |
5021134034143 has 2 divisors, whose sum is σ = 5021134034144. Its totient is φ = 5021134034142.
The previous prime is 5021134034101. The next prime is 5021134034153. The reversal of 5021134034143 is 3414304311205.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5021134034143 - 225 = 5021100479711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5021134034153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510567017071 + 2510567017072.
It is an arithmetic number, because the mean of its divisors is an integer number (2510567017072).
Almost surely, 25021134034143 is an apocalyptic number.
5021134034143 is a deficient number, since it is larger than the sum of its proper divisors (1).
5021134034143 is an equidigital number, since it uses as much as digits as its factorization.
5021134034143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 5021134034143 its reverse (3414304311205), we get a palindrome (8435438345348).
The spelling of 5021134034143 in words is "five trillion, twenty-one billion, one hundred thirty-four million, thirty-four thousand, one hundred forty-three".
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