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5022034050433 is a prime number
BaseRepresentation
bin100100100010100100010…
…0011100011110110000001
3122210002202012001212022011
41021011020203203312001
51124240111204103213
614403031322412521
71025554454046211
oct111051043436601
918702665055264
105022034050433
11166691832a7a4
12691379061141
132a5763ca8a2a
141350d3c6c241
158a97bd2903d
hex491488e3d81

5022034050433 has 2 divisors, whose sum is σ = 5022034050434. Its totient is φ = 5022034050432.

The previous prime is 5022034050421. The next prime is 5022034050503. The reversal of 5022034050433 is 3340504302205.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2587410582849 + 2434623467584 = 1608543^2 + 1560328^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5022034050433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5022034050395 and 5022034050404.

It is not a weakly prime, because it can be changed into another prime (5022034020433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2511017025216 + 2511017025217.

It is an arithmetic number, because the mean of its divisors is an integer number (2511017025217).

Almost surely, 25022034050433 is an apocalyptic number.

It is an amenable number.

5022034050433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5022034050433 is an equidigital number, since it uses as much as digits as its factorization.

5022034050433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 31.

Adding to 5022034050433 its reverse (3340504302205), we get a palindrome (8362538352638).

The spelling of 5022034050433 in words is "five trillion, twenty-two billion, thirty-four million, fifty thousand, four hundred thirty-three".