Base | Representation |
---|---|
bin | 100100100010110010001… |
… | …0101100010001001001111 |
3 | 122210010221200002102211011 |
4 | 1021011210111202021033 |
5 | 1124242040013314003 |
6 | 14403145452310051 |
7 | 1025602143520624 |
oct | 111054425421117 |
9 | 18703850072734 |
10 | 5022500135503 |
11 | 1667037432374 |
12 | 691489172327 |
13 | 2a5809717c06 |
14 | 135139b1634b |
15 | 8a9a7be346d |
hex | 4916456224f |
5022500135503 has 2 divisors, whose sum is σ = 5022500135504. Its totient is φ = 5022500135502.
The previous prime is 5022500135479. The next prime is 5022500135533. The reversal of 5022500135503 is 3055310052205.
5022500135503 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5022500135503 - 237 = 4885061182031 is a prime.
It is a super-2 number, since 2×50225001355032 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5022500135533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2511250067751 + 2511250067752.
It is an arithmetic number, because the mean of its divisors is an integer number (2511250067752).
Almost surely, 25022500135503 is an apocalyptic number.
5022500135503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5022500135503 is an equidigital number, since it uses as much as digits as its factorization.
5022500135503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 22500, while the sum is 31.
Adding to 5022500135503 its reverse (3055310052205), we get a palindrome (8077810187708).
The spelling of 5022500135503 in words is "five trillion, twenty-two billion, five hundred million, one hundred thirty-five thousand, five hundred three".
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