Base | Representation |
---|---|
bin | 10110110101111001011110… |
… | …00101101000000010000011 |
3 | 20120211222112012121200101212 |
4 | 23122330233011220002003 |
5 | 23040433411211434223 |
6 | 254455313034120335 |
7 | 13403012641544045 |
oct | 1332745705500203 |
9 | 216758465550355 |
10 | 50230432530563 |
11 | 1500667472799a |
12 | 5772bb22800ab |
13 | 220492b8c858c |
14 | c59247365a95 |
15 | 5c191eb9a278 |
hex | 2daf2f168083 |
50230432530563 has 2 divisors, whose sum is σ = 50230432530564. Its totient is φ = 50230432530562.
The previous prime is 50230432530437. The next prime is 50230432530569. The reversal of 50230432530563 is 36503523403205.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50230432530563 is a prime.
It is a super-3 number, since 3×502304325305633 (a number of 42 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 50230432530563.
It is not a weakly prime, because it can be changed into another prime (50230432530569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25115216265281 + 25115216265282.
It is an arithmetic number, because the mean of its divisors is an integer number (25115216265282).
Almost surely, 250230432530563 is an apocalyptic number.
50230432530563 is a deficient number, since it is larger than the sum of its proper divisors (1).
50230432530563 is an equidigital number, since it uses as much as digits as its factorization.
50230432530563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 41.
Adding to 50230432530563 its reverse (36503523403205), we get a palindrome (86733955933768).
The spelling of 50230432530563 in words is "fifty trillion, two hundred thirty billion, four hundred thirty-two million, five hundred thirty thousand, five hundred sixty-three".
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