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50230432530437 is a prime number
BaseRepresentation
bin10110110101111001011110…
…00101101000000000000101
320120211222112012121200020012
423122330233011220000011
523040433411211433222
6254455313034120005
713403012641543505
oct1332745705500005
9216758465550205
1050230432530437
1115006674727895
125772bb2280005
13220492b8c84c3
14c59247365a05
155c191eb9a1e2
hex2daf2f168005

50230432530437 has 2 divisors, whose sum is σ = 50230432530438. Its totient is φ = 50230432530436.

The previous prime is 50230432530361. The next prime is 50230432530563. The reversal of 50230432530437 is 73403523403205.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40184772009316 + 10045660521121 = 6339146^2 + 3169489^2 .

It is a cyclic number.

It is not a de Polignac number, because 50230432530437 - 210 = 50230432529413 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50230432530394 and 50230432530403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50230432530737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25115216265218 + 25115216265219.

It is an arithmetic number, because the mean of its divisors is an integer number (25115216265219).

Almost surely, 250230432530437 is an apocalyptic number.

It is an amenable number.

50230432530437 is a deficient number, since it is larger than the sum of its proper divisors (1).

50230432530437 is an equidigital number, since it uses as much as digits as its factorization.

50230432530437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 907200, while the sum is 41.

The spelling of 50230432530437 in words is "fifty trillion, two hundred thirty billion, four hundred thirty-two million, five hundred thirty thousand, four hundred thirty-seven".