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502323141193 is a prime number
BaseRepresentation
bin1110100111101001100…
…10101101101001001001
31210000120202121111211221
413103310302231221021
531212224211004233
61022433012122041
751202015151626
oct7236462555111
91700522544757
10502323141193
111840413548a5
128142b006321
13384a4536033
141a45399734d
15d0eea7642d
hex74f4cada49

502323141193 has 2 divisors, whose sum is σ = 502323141194. Its totient is φ = 502323141192.

The previous prime is 502323141163. The next prime is 502323141227. The reversal of 502323141193 is 391141323205.

It is an a-pointer prime, because the next prime (502323141227) can be obtained adding 502323141193 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 498362578704 + 3960562489 = 705948^2 + 62933^2 .

It is a cyclic number.

It is not a de Polignac number, because 502323141193 - 221 = 502321044041 is a prime.

It is a super-2 number, since 2×5023231411932 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (502323141163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251161570596 + 251161570597.

It is an arithmetic number, because the mean of its divisors is an integer number (251161570597).

Almost surely, 2502323141193 is an apocalyptic number.

It is an amenable number.

502323141193 is a deficient number, since it is larger than the sum of its proper divisors (1).

502323141193 is an equidigital number, since it uses as much as digits as its factorization.

502323141193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 34.

Adding to 502323141193 its reverse (391141323205), we get a palindrome (893464464398).

The spelling of 502323141193 in words is "five hundred two billion, three hundred twenty-three million, one hundred forty-one thousand, one hundred ninety-three".