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50248968514637 is a prime number
BaseRepresentation
bin10110110110011011111111…
…11010110010110001001101
320120220202101000100020100112
423123031333322302301031
523041234341414432022
6254512020224405405
713404240166033664
oct1333157772626115
9216822330306315
1050248968514637
11150135168140a2
125776705a76865
1322065c3b9c8a9
14c5a0c5033ddb
155c21571288e2
hex2db37feb2c4d

50248968514637 has 2 divisors, whose sum is σ = 50248968514638. Its totient is φ = 50248968514636.

The previous prime is 50248968514607. The next prime is 50248968514687. The reversal of 50248968514637 is 73641586984205.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49693673791876 + 555294722761 = 7049374^2 + 745181^2 .

It is a cyclic number.

It is not a de Polignac number, because 50248968514637 - 212 = 50248968510541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50248968514607) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25124484257318 + 25124484257319.

It is an arithmetic number, because the mean of its divisors is an integer number (25124484257319).

It is a 1-persistent number, because it is pandigital, but 2⋅50248968514637 = 100497937029274 is not.

Almost surely, 250248968514637 is an apocalyptic number.

It is an amenable number.

50248968514637 is a deficient number, since it is larger than the sum of its proper divisors (1).

50248968514637 is an equidigital number, since it uses as much as digits as its factorization.

50248968514637 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 348364800, while the sum is 68.

The spelling of 50248968514637 in words is "fifty trillion, two hundred forty-eight billion, nine hundred sixty-eight million, five hundred fourteen thousand, six hundred thirty-seven".