Base | Representation |
---|---|
bin | 101110110011001010… |
… | …011001011000000111 |
3 | 11210201001011020121101 |
4 | 232303022121120013 |
5 | 1310403111043203 |
6 | 35030150200531 |
7 | 3426153044302 |
oct | 566312313007 |
9 | 153631136541 |
10 | 50250487303 |
11 | 1a3470a9955 |
12 | 98a4953147 |
13 | 497a923173 |
14 | 2609ad5b39 |
15 | 149187341d |
hex | bb3299607 |
50250487303 has 2 divisors, whose sum is σ = 50250487304. Its totient is φ = 50250487302.
The previous prime is 50250487271. The next prime is 50250487321. The reversal of 50250487303 is 30378405205.
50250487303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50250487303 - 25 = 50250487271 is a prime.
It is a super-2 number, since 2×502504873032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50250487373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25125243651 + 25125243652.
It is an arithmetic number, because the mean of its divisors is an integer number (25125243652).
Almost surely, 250250487303 is an apocalyptic number.
50250487303 is a deficient number, since it is larger than the sum of its proper divisors (1).
50250487303 is an equidigital number, since it uses as much as digits as its factorization.
50250487303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 37.
The spelling of 50250487303 in words is "fifty billion, two hundred fifty million, four hundred eighty-seven thousand, three hundred three".
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