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502525230041 is a prime number
BaseRepresentation
bin1110101000000001101…
…01100111101111011001
31210001002211212200122002
413110000311213233121
531213132424330131
61022505031410345
751210020656142
oct7240065475731
91701084780562
10502525230041
1118413543417a
12814868239b5
1338507372033
141a472760ac9
15d1126946cb
hex7500d67bd9

502525230041 has 2 divisors, whose sum is σ = 502525230042. Its totient is φ = 502525230040.

The previous prime is 502525230029. The next prime is 502525230043. The reversal of 502525230041 is 140032525205.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 329659705600 + 172865524441 = 574160^2 + 415771^2 .

It is a cyclic number.

It is not a de Polignac number, because 502525230041 - 214 = 502525213657 is a prime.

It is a super-3 number, since 3×5025252300413 (a number of 36 digits) contains 333 as substring.

Together with 502525230043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 502525229986 and 502525230013.

It is not a weakly prime, because it can be changed into another prime (502525230043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251262615020 + 251262615021.

It is an arithmetic number, because the mean of its divisors is an integer number (251262615021).

Almost surely, 2502525230041 is an apocalyptic number.

It is an amenable number.

502525230041 is a deficient number, since it is larger than the sum of its proper divisors (1).

502525230041 is an equidigital number, since it uses as much as digits as its factorization.

502525230041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12000, while the sum is 29.

Adding to 502525230041 its reverse (140032525205), we get a palindrome (642557755246).

The spelling of 502525230041 in words is "five hundred two billion, five hundred twenty-five million, two hundred thirty thousand, forty-one".