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50253052775533 is a prime number
BaseRepresentation
bin10110110110100011100110…
…10111000000110001101101
320120221010220122121012000121
423123101303113000301231
523041321223002304113
6254513533404324541
713404443331501106
oct1333216327006155
9216833818535017
1050253052775533
1115015222219823
125777465843751
132206ac50b3c0a
14c5a39163d3ad
155c22e5994e8d
hex2db4735c0c6d

50253052775533 has 2 divisors, whose sum is σ = 50253052775534. Its totient is φ = 50253052775532.

The previous prime is 50253052775503. The next prime is 50253052775591. The reversal of 50253052775533 is 33557725035205.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25810332069769 + 24442720705764 = 5080387^2 + 4943958^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50253052775533 is a prime.

It is a super-3 number, since 3×502530527755333 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50253052775503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25126526387766 + 25126526387767.

It is an arithmetic number, because the mean of its divisors is an integer number (25126526387767).

Almost surely, 250253052775533 is an apocalyptic number.

It is an amenable number.

50253052775533 is a deficient number, since it is larger than the sum of its proper divisors (1).

50253052775533 is an equidigital number, since it uses as much as digits as its factorization.

50253052775533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16537500, while the sum is 52.

The spelling of 50253052775533 in words is "fifty trillion, two hundred fifty-three billion, fifty-two million, seven hundred seventy-five thousand, five hundred thirty-three".