Base | Representation |
---|---|
bin | 10110110110100011101101… |
… | …11010111110010001100001 |
3 | 20120221011001211001020101100 |
4 | 23123101312322332101201 |
5 | 23041321333302042423 |
6 | 254513543341225013 |
7 | 13404444655441266 |
oct | 1333216672762141 |
9 | 216834054036340 |
10 | 50253112534113 |
11 | 15015252a25285 |
12 | 5777481862169 |
13 | 2206b045a8018 |
14 | c5a39955726d |
15 | 5c22ead4b343 |
hex | 2db476ebe461 |
50253112534113 has 24 divisors (see below), whose sum is σ = 72644303895488. Its totient is φ = 33476017688352.
The previous prime is 50253112534109. The next prime is 50253112534159. The reversal of 50253112534113 is 31143521135205.
It is a happy number.
50253112534113 is a `hidden beast` number, since 5 + 0 + 2 + 5 + 3 + 1 + 1 + 2 + 534 + 113 = 666.
It is not a de Polignac number, because 50253112534113 - 22 = 50253112534109 is a prime.
It is a super-3 number, since 3×502531125341133 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (50253112574113) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 76763931 + ... + 77415807.
Almost surely, 250253112534113 is an apocalyptic number.
It is an amenable number.
50253112534113 is a deficient number, since it is larger than the sum of its proper divisors (22391191361375).
50253112534113 is a wasteful number, since it uses less digits than its factorization.
50253112534113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 658533 (or 658530 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 36.
Adding to 50253112534113 its reverse (31143521135205), we get a palindrome (81396633669318).
The spelling of 50253112534113 in words is "fifty trillion, two hundred fifty-three billion, one hundred twelve million, five hundred thirty-four thousand, one hundred thirteen".
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