Base | Representation |
---|---|
bin | 100100100100000110111… |
… | …0011100011010100100111 |
3 | 122210102021211002220120112 |
4 | 1021020031303203110213 |
5 | 1124313400344313101 |
6 | 14404335540323235 |
7 | 1026032456501051 |
oct | 111101563432447 |
9 | 18712254086515 |
10 | 5025343354151 |
11 | 166826634964a |
12 | 691b413a351b |
13 | 2a5b70797a03 |
14 | 13532958a8d1 |
15 | 8aac26186bb |
hex | 4920dce3527 |
5025343354151 has 4 divisors (see below), whose sum is σ = 5025444964704. Its totient is φ = 5025241743600.
The previous prime is 5025343354091. The next prime is 5025343354159. The reversal of 5025343354151 is 1514533435205.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5025343354151 - 210 = 5025343353127 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5025343354099 and 5025343354108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5025343354159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50731055 + ... + 50830016.
It is an arithmetic number, because the mean of its divisors is an integer number (1256361241176).
Almost surely, 25025343354151 is an apocalyptic number.
5025343354151 is a deficient number, since it is larger than the sum of its proper divisors (101610553).
5025343354151 is a wasteful number, since it uses less digits than its factorization.
5025343354151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101610552.
The product of its (nonzero) digits is 540000, while the sum is 41.
Adding to 5025343354151 its reverse (1514533435205), we get a palindrome (6539876789356).
The spelling of 5025343354151 in words is "five trillion, twenty-five billion, three hundred forty-three million, three hundred fifty-four thousand, one hundred fifty-one".
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