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5025345021431 = 7717906431633
BaseRepresentation
bin100100100100000110111…
…1001111010010111110111
3122210102021221020121122122
41021020031321322113313
51124313401311141211
614404340040150155
71026032506613660
oct111101571722767
918712257217578
105025345021431
111668267288269
12691b41a6835b
132a5b70c2c877
141353298a2367
158aac28476db
hex4920de7a5f7

5025345021431 has 4 divisors (see below), whose sum is σ = 5743251453072. Its totient is φ = 4307438589792.

The previous prime is 5025345021293. The next prime is 5025345021439. The reversal of 5025345021431 is 1341205435205.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5025345021431 - 210 = 5025345020407 is a prime.

It is a super-2 number, since 2×50253450214312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5025345021391 and 5025345021400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5025345021439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 358953215810 + ... + 358953215823.

It is an arithmetic number, because the mean of its divisors is an integer number (1435812863268).

Almost surely, 25025345021431 is an apocalyptic number.

5025345021431 is a deficient number, since it is larger than the sum of its proper divisors (717906431641).

5025345021431 is an equidigital number, since it uses as much as digits as its factorization.

5025345021431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 717906431640.

The product of its (nonzero) digits is 72000, while the sum is 35.

The spelling of 5025345021431 in words is "five trillion, twenty-five billion, three hundred forty-five million, twenty-one thousand, four hundred thirty-one".

Divisors: 1 7 717906431633 5025345021431