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50254310537 is a prime number
BaseRepresentation
bin101110110011011000…
…111110110010001001
311210201022100111002122
4232303120332302021
51310410100414122
635030404141025
73426230406614
oct566330766211
9153638314078
1050254310537
111a349280352
1298a6097775
13497b661432
14260a40d17b
151491d7b142
hexbb363ec89

50254310537 has 2 divisors, whose sum is σ = 50254310538. Its totient is φ = 50254310536.

The previous prime is 50254310497. The next prime is 50254310539. The reversal of 50254310537 is 73501345205.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25904580601 + 24349729936 = 160949^2 + 156044^2 .

It is a cyclic number.

It is not a de Polignac number, because 50254310537 - 222 = 50250116233 is a prime.

Together with 50254310539, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 50254310497 and 50254310506.

It is not a weakly prime, because it can be changed into another prime (50254310539) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25127155268 + 25127155269.

It is an arithmetic number, because the mean of its divisors is an integer number (25127155269).

Almost surely, 250254310537 is an apocalyptic number.

It is an amenable number.

50254310537 is a deficient number, since it is larger than the sum of its proper divisors (1).

50254310537 is an equidigital number, since it uses as much as digits as its factorization.

50254310537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63000, while the sum is 35.

The spelling of 50254310537 in words is "fifty billion, two hundred fifty-four million, three hundred ten thousand, five hundred thirty-seven".