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50255110993 = 86935781101
BaseRepresentation
bin101110110011011100…
…000010001101010001
311210201100212011010011
4232303130002031101
51310410302022433
635030433234521
73426240252403
oct566334021521
9153640764104
1050255110993
111a34977778a
1298a6402a41
13497b881889
14260a57ab73
151491e883cd
hexbb3702351

50255110993 has 4 divisors (see below), whose sum is σ = 50260900788. Its totient is φ = 50249321200.

The previous prime is 50255110967. The next prime is 50255111029. The reversal of 50255110993 is 39901155205.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12242979904 + 38012131089 = 110648^2 + 194967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50255110993 is a prime.

It is a super-3 number, since 3×502551109933 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (50255110943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2881858 + ... + 2899243.

It is an arithmetic number, because the mean of its divisors is an integer number (12565225197).

Almost surely, 250255110993 is an apocalyptic number.

It is an amenable number.

50255110993 is a deficient number, since it is larger than the sum of its proper divisors (5789795).

50255110993 is an equidigital number, since it uses as much as digits as its factorization.

50255110993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5789794.

The product of its (nonzero) digits is 60750, while the sum is 40.

The spelling of 50255110993 in words is "fifty billion, two hundred fifty-five million, one hundred ten thousand, nine hundred ninety-three".

Divisors: 1 8693 5781101 50255110993