Base | Representation |
---|---|
bin | 101110110011101110… |
… | …101011110101100011 |
3 | 11210201201001112201011 |
4 | 232303232223311203 |
5 | 1310413030000344 |
6 | 35031130121351 |
7 | 3426326644351 |
oct | 566356536543 |
9 | 153651045634 |
10 | 50260000099 |
11 | 1a351506a71 |
12 | 98a7b80257 |
13 | 497c8a403a |
14 | 260b0907d1 |
15 | 1492601d34 |
hex | bb3babd63 |
50260000099 has 2 divisors, whose sum is σ = 50260000100. Its totient is φ = 50260000098.
The previous prime is 50260000069. The next prime is 50260000103. The reversal of 50260000099 is 99000006205.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50260000099 - 25 = 50260000067 is a prime.
It is a super-3 number, since 3×502600000993 (a number of 33 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 50260000099.
It is not a weakly prime, because it can be changed into another prime (50260000009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25130000049 + 25130000050.
It is an arithmetic number, because the mean of its divisors is an integer number (25130000050).
Almost surely, 250260000099 is an apocalyptic number.
50260000099 is a deficient number, since it is larger than the sum of its proper divisors (1).
50260000099 is an equidigital number, since it uses as much as digits as its factorization.
50260000099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4860, while the sum is 31.
The spelling of 50260000099 in words is "fifty billion, two hundred sixty million, ninety-nine", and thus it is an aban number.
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