Base | Representation |
---|---|
bin | 10110110111010110101111… |
… | …01000111100001000110111 |
3 | 20121000202202211210201002120 |
4 | 23123223113220330020313 |
5 | 23042243433240004003 |
6 | 254534313425011023 |
7 | 13406434533531321 |
oct | 1333532750741067 |
9 | 217022684721076 |
10 | 50280505000503 |
11 | 1502592a298758 |
12 | 5780847483a73 |
13 | 220957b69010b |
14 | c5b83755c611 |
15 | 5c2da0aa7853 |
hex | 2dbad7a3c237 |
50280505000503 has 4 divisors (see below), whose sum is σ = 67040673334008. Its totient is φ = 33520336667000.
The previous prime is 50280505000433. The next prime is 50280505000507. The reversal of 50280505000503 is 30500050508205.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 50280505000503 - 220 = 50280503951927 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50280505000507) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8380084166748 + ... + 8380084166753.
It is an arithmetic number, because the mean of its divisors is an integer number (16760168333502).
Almost surely, 250280505000503 is an apocalyptic number.
50280505000503 is a deficient number, since it is larger than the sum of its proper divisors (16760168333505).
50280505000503 is a wasteful number, since it uses less digits than its factorization.
50280505000503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16760168333504.
The product of its (nonzero) digits is 30000, while the sum is 33.
Adding to 50280505000503 its reverse (30500050508205), we get a palindrome (80780555508708).
The spelling of 50280505000503 in words is "fifty trillion, two hundred eighty billion, five hundred five million, five hundred three", and thus it is an aban number.
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