Base | Representation |
---|---|
bin | 101110110110001100… |
… | …000011111100001001 |
3 | 11210211120200112101111 |
4 | 232312030003330021 |
5 | 1311004110133213 |
6 | 35035202250321 |
7 | 3430340421322 |
oct | 566614037411 |
9 | 153746615344 |
10 | 50301255433 |
11 | 1a372824790 |
12 | 98b99569a1 |
13 | 49882ba090 |
14 | 261274d449 |
15 | 1496050a3d |
hex | bb6303f09 |
50301255433 has 32 divisors (see below), whose sum is σ = 61057446912. Its totient is φ = 40811731200.
The previous prime is 50301255401. The next prime is 50301255497. The reversal of 50301255433 is 33455210305.
50301255433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 50301255433 - 25 = 50301255401 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 50301255395 and 50301255404.
It is not an unprimeable number, because it can be changed into a prime (50301255833) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5479035 + ... + 5488207.
It is an arithmetic number, because the mean of its divisors is an integer number (1908045216).
Almost surely, 250301255433 is an apocalyptic number.
It is an amenable number.
50301255433 is a deficient number, since it is larger than the sum of its proper divisors (10756191479).
50301255433 is a wasteful number, since it uses less digits than its factorization.
50301255433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10465.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 50301255433 its reverse (33455210305), we get a palindrome (83756465738).
The spelling of 50301255433 in words is "fifty billion, three hundred one million, two hundred fifty-five thousand, four hundred thirty-three".
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