Base | Representation |
---|---|
bin | 111001001100001100000010… |
… | …0111110011111100000000101 |
3 | 2102222011100020021222100112122 |
4 | 1302120120010332133200011 |
5 | 1011414002330242031432 |
6 | 4541523032012055325 |
7 | 210650223666402602 |
oct | 16230300476374005 |
9 | 2388140207870478 |
10 | 503052423002117 |
11 | 13631937526498a |
12 | 48506b1a764545 |
13 | 18790841c43c71 |
14 | 8c31c1d7ad6a9 |
15 | 3d258345a3612 |
hex | 1c98604f9f805 |
503052423002117 has 2 divisors, whose sum is σ = 503052423002118. Its totient is φ = 503052423002116.
The previous prime is 503052423002083. The next prime is 503052423002141. The reversal of 503052423002117 is 711200324250305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 341259339918436 + 161793083083681 = 18473206^2 + 12719791^2 .
It is a cyclic number.
It is not a de Polignac number, because 503052423002117 - 220 = 503052421953541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (503052423002617) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251526211501058 + 251526211501059.
It is an arithmetic number, because the mean of its divisors is an integer number (251526211501059).
Almost surely, 2503052423002117 is an apocalyptic number.
It is an amenable number.
503052423002117 is a deficient number, since it is larger than the sum of its proper divisors (1).
503052423002117 is an equidigital number, since it uses as much as digits as its factorization.
503052423002117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 503052423002117 in words is "five hundred three trillion, fifty-two billion, four hundred twenty-three million, two thousand, one hundred seventeen".
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