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503052423002117 is a prime number
BaseRepresentation
bin111001001100001100000010…
…0111110011111100000000101
32102222011100020021222100112122
41302120120010332133200011
51011414002330242031432
64541523032012055325
7210650223666402602
oct16230300476374005
92388140207870478
10503052423002117
1113631937526498a
1248506b1a764545
1318790841c43c71
148c31c1d7ad6a9
153d258345a3612
hex1c98604f9f805

503052423002117 has 2 divisors, whose sum is σ = 503052423002118. Its totient is φ = 503052423002116.

The previous prime is 503052423002083. The next prime is 503052423002141. The reversal of 503052423002117 is 711200324250305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 341259339918436 + 161793083083681 = 18473206^2 + 12719791^2 .

It is a cyclic number.

It is not a de Polignac number, because 503052423002117 - 220 = 503052421953541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (503052423002617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251526211501058 + 251526211501059.

It is an arithmetic number, because the mean of its divisors is an integer number (251526211501059).

Almost surely, 2503052423002117 is an apocalyptic number.

It is an amenable number.

503052423002117 is a deficient number, since it is larger than the sum of its proper divisors (1).

503052423002117 is an equidigital number, since it uses as much as digits as its factorization.

503052423002117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50400, while the sum is 35.

The spelling of 503052423002117 in words is "five hundred three trillion, fifty-two billion, four hundred twenty-three million, two thousand, one hundred seventeen".