50313310537 has 4 divisors (see below), whose sum is σ = 57500926336. Its totient is φ = 43125694740.

The previous prime is 50313310493. The next prime is 50313310561. The reversal of 50313310537 is 73501331305.

50313310537 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 73501331305 = 5 ⋅14700266261.

It is a cyclic number.

It is not a de Polignac number, because 50313310537 - 2³¹ = 48165826889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50313310499 and 50313310508.

It is not an unprimeable number, because it can be changed into a prime (50313310237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3593807889 + ... + 3593807902.

It is an arithmetic number, because the mean of its divisors is an integer number (14375231584).

Almost surely, 2^50313310537 is an apocalyptic number.

It is an amenable number.

50313310537 is a deficient number, since it is larger than the sum of its proper divisors (7187615799).

50313310537 is an equidigital number, since it uses as much as digits as its factorization.

50313310537 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7187615798.

The product of its (nonzero) digits is 14175, while the sum is 31.

The spelling of 50313310537 in words is "fifty billion, three hundred thirteen million, three hundred ten thousand, five hundred thirty-seven".