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5031401335067 is a prime number
BaseRepresentation
bin100100100110111011011…
…1000111010100100011011
3122210222221000021020010002
41021031312320322210123
51124413302220210232
614411221024043215
71026335546464022
oct111156670724433
918728830236102
105031401335067
11166a894981348
1269315216350b
132a65c78846c3
14135741d6d8b9
158ad293a5b62
hex49376e3a91b

5031401335067 has 2 divisors, whose sum is σ = 5031401335068. Its totient is φ = 5031401335066.

The previous prime is 5031401335031. The next prime is 5031401335087. The reversal of 5031401335067 is 7605331041305.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5031401335067 is a prime.

It is a super-3 number, since 3×50314013350673 (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 5031401335067.

It is not a weakly prime, because it can be changed into another prime (5031401335087) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2515700667533 + 2515700667534.

It is an arithmetic number, because the mean of its divisors is an integer number (2515700667534).

Almost surely, 25031401335067 is an apocalyptic number.

5031401335067 is a deficient number, since it is larger than the sum of its proper divisors (1).

5031401335067 is an equidigital number, since it uses as much as digits as its factorization.

5031401335067 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 113400, while the sum is 38.

The spelling of 5031401335067 in words is "five trillion, thirty-one billion, four hundred one million, three hundred thirty-five thousand, sixty-seven".