50314114011153 has 4 divisors (see below), whose sum is σ = 67085485348208. Its totient is φ = 33542742674100.

The previous prime is 50314114011067. The next prime is 50314114011167. The reversal of 50314114011153 is 35111041141305.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 50314114011153 - 2³² = 50309819043857 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 50314114011153.

It is not an unprimeable number, because it can be changed into a prime (50314114011253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8385685668523 + ... + 8385685668528.

It is an arithmetic number, because the mean of its divisors is an integer number (16771371337052).

Almost surely, 2^{50314114011153} is an apocalyptic number.

It is an amenable number.

50314114011153 is a deficient number, since it is larger than the sum of its proper divisors (16771371337055).

50314114011153 is a wasteful number, since it uses less digits than its factorization.

50314114011153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16771371337054.

The product of its (nonzero) digits is 3600, while the sum is 30.

Adding to 50314114011153 its reverse (35111041141305), we get a palindrome (85425155152458).

The spelling of 50314114011153 in words is "fifty trillion, three hundred fourteen billion, one hundred fourteen million, eleven thousand, one hundred fifty-three".