Base | Representation |
---|---|
bin | 101110110110111110… |
… | …111111101000001001 |
3 | 11210212111210212110011 |
4 | 232312332333220021 |
5 | 1311021014411423 |
6 | 35040400351521 |
7 | 3430562050441 |
oct | 566676775011 |
9 | 153774725404 |
10 | 50314607113 |
11 | 1a37a314031 |
12 | 99023155a1 |
13 | 498acb3394 |
14 | 2614427121 |
15 | 14972dbb0d |
hex | bb6fbfa09 |
50314607113 has 2 divisors, whose sum is σ = 50314607114. Its totient is φ = 50314607112.
The previous prime is 50314607051. The next prime is 50314607117. The reversal of 50314607113 is 31170641305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29081163024 + 21233444089 = 170532^2 + 145717^2 .
It is a cyclic number.
It is not a de Polignac number, because 50314607113 - 225 = 50281052681 is a prime.
It is not a weakly prime, because it can be changed into another prime (50314607117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25157303556 + 25157303557.
It is an arithmetic number, because the mean of its divisors is an integer number (25157303557).
Almost surely, 250314607113 is an apocalyptic number.
It is an amenable number.
50314607113 is a deficient number, since it is larger than the sum of its proper divisors (1).
50314607113 is an equidigital number, since it uses as much as digits as its factorization.
50314607113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7560, while the sum is 31.
The spelling of 50314607113 in words is "fifty billion, three hundred fourteen million, six hundred seven thousand, one hundred thirteen".
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