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5031514391 is a prime number
BaseRepresentation
bin1001010111110011…
…01101000100010111
3110222122200102011212
410223321231010113
540301031430031
62151134452035
7235454111111
oct45371550427
913878612155
105031514391
112152182262
12b8506401b
13622543c67
1435a3463b1
151e6ace12b
hex12be6d117

5031514391 has 2 divisors, whose sum is σ = 5031514392. Its totient is φ = 5031514390.

The previous prime is 5031514381. The next prime is 5031514459. The reversal of 5031514391 is 1934151305.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5031514391 is a prime.

It is a super-2 number, since 2×50315143912 = 50632274133680201762, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5031514351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2515757195 + 2515757196.

It is an arithmetic number, because the mean of its divisors is an integer number (2515757196).

Almost surely, 25031514391 is an apocalyptic number.

5031514391 is a deficient number, since it is larger than the sum of its proper divisors (1).

5031514391 is an equidigital number, since it uses as much as digits as its factorization.

5031514391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 32.

The square root of 5031514391 is about 70933.1684827345. The cubic root of 5031514391 is about 1713.5610151490.

Adding to 5031514391 its reverse (1934151305), we get a palindrome (6965665696).

The spelling of 5031514391 in words is "five billion, thirty-one million, five hundred fourteen thousand, three hundred ninety-one".