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50323500345551 is a prime number
BaseRepresentation
bin10110111000100110110100…
…10111001010100011001111
320121011212202021010112112112
423130103122113022203033
523044000012042024201
6255010144044254235
713412516152116446
oct1334233227124317
9217155667115475
1050323500345551
1115042093017874
12578904654137b
1322106411871a4
14c5d95587dd5d
155c406a5140bb
hex2dc4da5ca8cf

50323500345551 has 2 divisors, whose sum is σ = 50323500345552. Its totient is φ = 50323500345550.

The previous prime is 50323500345467. The next prime is 50323500345571. The reversal of 50323500345551 is 15554300532305.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 50323500345551 - 234 = 50306320476367 is a prime.

It is a super-3 number, since 3×503235003455513 (a number of 42 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50323500345499 and 50323500345508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50323500345571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25161750172775 + 25161750172776.

It is an arithmetic number, because the mean of its divisors is an integer number (25161750172776).

Almost surely, 250323500345551 is an apocalyptic number.

50323500345551 is a deficient number, since it is larger than the sum of its proper divisors (1).

50323500345551 is an equidigital number, since it uses as much as digits as its factorization.

50323500345551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 675000, while the sum is 41.

Adding to 50323500345551 its reverse (15554300532305), we get a palindrome (65877800877856).

The spelling of 50323500345551 in words is "fifty trillion, three hundred twenty-three billion, five hundred million, three hundred forty-five thousand, five hundred fifty-one".