Base | Representation |
---|---|
bin | 100100100111110010000… |
… | …1100111101001011110111 |
3 | 122211011122211012120012002 |
4 | 1021033210030331023313 |
5 | 1124431031214231312 |
6 | 14412123020245515 |
7 | 1026432156123524 |
oct | 111174414751367 |
9 | 18734584176162 |
10 | 5033235305207 |
11 | 167064612824a |
12 | 6935843a089b |
13 | 2a682a809835 |
14 | 13587776a14b |
15 | 8add53be4c2 |
hex | 493e433d2f7 |
5033235305207 has 2 divisors, whose sum is σ = 5033235305208. Its totient is φ = 5033235305206.
The previous prime is 5033235305183. The next prime is 5033235305297. The reversal of 5033235305207 is 7025035323305.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5033235305207 is a prime.
It is a super-3 number, since 3×50332353052073 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5033235305297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516617652603 + 2516617652604.
It is an arithmetic number, because the mean of its divisors is an integer number (2516617652604).
Almost surely, 25033235305207 is an apocalyptic number.
5033235305207 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033235305207 is an equidigital number, since it uses as much as digits as its factorization.
5033235305207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 283500, while the sum is 38.
The spelling of 5033235305207 in words is "five trillion, thirty-three billion, two hundred thirty-five million, three hundred five thousand, two hundred seven".
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