Base | Representation |
---|---|
bin | 100100100111110100011… |
… | …1101000110000111000101 |
3 | 122211011212101020011220100 |
4 | 1021033220331012013011 |
5 | 1124431212122033131 |
6 | 14412134545154313 |
7 | 1026434144605614 |
oct | 111175075060705 |
9 | 18734771204810 |
10 | 5033315033541 |
11 | 1670687133333 |
12 | 6935a702b999 |
13 | 2a68411a3372 |
14 | 1358841a187b |
15 | 8addc3bc7e6 |
hex | 493e8f461c5 |
5033315033541 has 24 divisors (see below), whose sum is σ = 7637361638400. Its totient is φ = 3188108870496.
The previous prime is 5033315033533. The next prime is 5033315033557. The reversal of 5033315033541 is 1453305133305.
5033315033541 is a `hidden beast` number, since 5 + 0 + 3 + 3 + 31 + 50 + 33 + 541 = 666.
It is not a de Polignac number, because 5033315033541 - 23 = 5033315033533 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5033315033496 and 5033315033505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5033315033561) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 81564901 + ... + 81626586.
It is an arithmetic number, because the mean of its divisors is an integer number (318223401600).
Almost surely, 25033315033541 is an apocalyptic number.
It is an amenable number.
5033315033541 is a deficient number, since it is larger than the sum of its proper divisors (2604046604859).
5033315033541 is a wasteful number, since it uses less digits than its factorization.
5033315033541 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 163191665 (or 163191662 counting only the distinct ones).
The product of its (nonzero) digits is 121500, while the sum is 36.
The spelling of 5033315033541 in words is "five trillion, thirty-three billion, three hundred fifteen million, thirty-three thousand, five hundred forty-one".
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