Base | Representation |
---|---|
bin | 100100100111110100101… |
… | …0100010101010101111011 |
3 | 122211011212210200200010221 |
4 | 1021033221110111111323 |
5 | 1124431220202001433 |
6 | 14412135323520511 |
7 | 1026434250436645 |
oct | 111175124252573 |
9 | 18734783620127 |
10 | 5033321125243 |
11 | 167068a6140a4 |
12 | 6935a9089137 |
13 | 2a6842527018 |
14 | 135884d09895 |
15 | 8addcbc272d |
hex | 493e951557b |
5033321125243 has 2 divisors, whose sum is σ = 5033321125244. Its totient is φ = 5033321125242.
The previous prime is 5033321125213. The next prime is 5033321125279. The reversal of 5033321125243 is 3425211233305.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5033321125243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5033321125199 and 5033321125208.
It is not a weakly prime, because it can be changed into another prime (5033321125213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516660562621 + 2516660562622.
It is an arithmetic number, because the mean of its divisors is an integer number (2516660562622).
Almost surely, 25033321125243 is an apocalyptic number.
5033321125243 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033321125243 is an equidigital number, since it uses as much as digits as its factorization.
5033321125243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 5033321125243 its reverse (3425211233305), we get a palindrome (8458532358548).
The spelling of 5033321125243 in words is "five trillion, thirty-three billion, three hundred twenty-one million, one hundred twenty-five thousand, two hundred forty-three".
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