5033341231 has 2 divisors, whose sum is σ = 5033341232. Its totient is φ = 5033341230.

The previous prime is 5033341223. The next prime is 5033341267. The reversal of 5033341231 is 1321433305.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5033341231 - 2³ = 5033341223 is a prime.

It is a super-2 number, since 2×5033341231² = 50669047895369190722, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5033341196 and 5033341205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5033341211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516670615 + 2516670616.

It is an arithmetic number, because the mean of its divisors is an integer number (2516670616).

Almost surely, 2^5033341231 is an apocalyptic number.

5033341231 is a deficient number, since it is larger than the sum of its proper divisors (1).

5033341231 is an equidigital number, since it uses as much as digits as its factorization.

5033341231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 25.

The square root of 5033341231 is about 70946.0445056664. The cubic root of 5033341231 is about 1713.7683763777.

Adding to 5033341231 its reverse (1321433305), we get a palindrome (6354774536).

The spelling of 5033341231 in words is "five billion, thirty-three million, three hundred forty-one thousand, two hundred thirty-one".