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5033544051241 is a prime number
BaseRepresentation
bin100100100111111011010…
…0110101110101000101001
3122211012110100011111010101
41021033312212232220221
51124432144234114431
614412213405545401
71026442625330656
oct111176646565051
918735410144111
105033544051241
111670794435762
1269364b875261
132a687977a4b4
141358a6778c2d
158ae02559961
hex493f69aea29

5033544051241 has 2 divisors, whose sum is σ = 5033544051242. Its totient is φ = 5033544051240.

The previous prime is 5033544051203. The next prime is 5033544051253. The reversal of 5033544051241 is 1421504453305.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3330610400016 + 1702933651225 = 1824996^2 + 1304965^2 .

It is a cyclic number.

It is not a de Polignac number, because 5033544051241 - 225 = 5033510496809 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5033544051241.

It is not a weakly prime, because it can be changed into another prime (5033544051841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516772025620 + 2516772025621.

It is an arithmetic number, because the mean of its divisors is an integer number (2516772025621).

Almost surely, 25033544051241 is an apocalyptic number.

It is an amenable number.

5033544051241 is a deficient number, since it is larger than the sum of its proper divisors (1).

5033544051241 is an equidigital number, since it uses as much as digits as its factorization.

5033544051241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 37.

The spelling of 5033544051241 in words is "five trillion, thirty-three billion, five hundred forty-four million, fifty-one thousand, two hundred forty-one".