50340050437 has 2 divisors, whose sum is σ = 50340050438. Its totient is φ = 50340050436.

The previous prime is 50340050417. The next prime is 50340050473. The reversal of 50340050437 is 73405004305.

Together with next prime (50340050473) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43564455841 + 6775594596 = 208721^2 + 82314^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-50340050437 is a prime.

It is a super-3 number, since 3×50340050437³ (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50340050399 and 50340050408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50340050417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25170025218 + 25170025219.

It is an arithmetic number, because the mean of its divisors is an integer number (25170025219).

Almost surely, 2^50340050437 is an apocalyptic number.

It is an amenable number.

50340050437 is a deficient number, since it is larger than the sum of its proper divisors (1).

50340050437 is an equidigital number, since it uses as much as digits as its factorization.

50340050437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25200, while the sum is 31.

The spelling of 50340050437 in words is "fifty billion, three hundred forty million, fifty thousand, four hundred thirty-seven".