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5034040143001 is a prime number
BaseRepresentation
bin100100101000001010000…
…1011001010110010011001
3122211020201220122120002021
41021100110023022302121
51124434203234034001
614412334530534441
71026461131126432
oct111202413126231
918736656576067
105034040143001
111670a19472851
12693769a37421
132a692849470c
141359125d4489
158ae30d9eba1
hex494142cac99

5034040143001 has 2 divisors, whose sum is σ = 5034040143002. Its totient is φ = 5034040143000.

The previous prime is 5034040142959. The next prime is 5034040143049. The reversal of 5034040143001 is 1003410404305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4795876622601 + 238163520400 = 2189949^2 + 488020^2 .

It is a cyclic number.

It is not a de Polignac number, because 5034040143001 - 221 = 5034038045849 is a prime.

It is a super-2 number, since 2×50340401430012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5034040143071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517020071500 + 2517020071501.

It is an arithmetic number, because the mean of its divisors is an integer number (2517020071501).

Almost surely, 25034040143001 is an apocalyptic number.

It is an amenable number.

5034040143001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034040143001 is an equidigital number, since it uses as much as digits as its factorization.

5034040143001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 5034040143001 its reverse (1003410404305), we get a palindrome (6037450547306).

The spelling of 5034040143001 in words is "five trillion, thirty-four billion, forty million, one hundred forty-three thousand, one".